12y^2-28y-63/3y+8

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Solution for 12y^2-28y-63/3y+8 equation: 


y in (-oo:+oo)

12*y^2-(28*y)-((63/3)*y)+8 = 0

12*y^2-28*y-21*y+8 = 0

12*y^2-49*y+8 = 0

DELTA = (-49)^2-(4*8*12)

DELTA = 2017

DELTA > 0

y = (2017^(1/2)+49)/(2*12) or y = (49-2017^(1/2))/(2*12)

y = (2017^(1/2)+49)/24 or y = (49-2017^(1/2))/24

y in { (49-2017^(1/2))/24, (2017^(1/2)+49)/24 }

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